Answer
Friction force=μmg=0.26×65×9.81=165.78N\mu mg\\=0.26\times65\times9.81\\=165.78Nμmg=0.26×65×9.81=165.78N
Applied force(F) =780N
Acceleration can be given as
F−f=maa=780−165.7865a=9.45m/s2F-f=ma\\a=\frac{780-165.78}{65}\\a=9.45m/s^2F−f=maa=65780−165.78a=9.45m/s2
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