Answer
length of track(s) =30 m
Inclination "\\theta=20.0\u00b0"
Car will have acceleration due to gravity
"a=gsin\\theta\\\\=9.8\\times sin20\u00b0\\\\=9.8\\times 0.34\\\\a=3.33m\/s^2"
Time taken by car to reach the bottom can be given as
"t=\\sqrt{\\frac{2s}{a}}\\\\t=\\sqrt{\\frac{2\\times30}{3.33}}\\\\t=18.01second\\\\t=18s"
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