Answer to Question #141127 in Classical Mechanics for Dan Koepsell

Question

Accelerometer suspended in a vehicle braking from 50km/HR to 0 in a distance of 60 m. What angle does it make with vertical?

Answer 1

As per the question,

Initial speed $(u)=50km/hr = 50\times\frac{1000}{3600}m/sec=\frac{125}{9}m/s$

Final speed $(v)=0$

Covered distance $(d)=60m$

Let the acceleration is $=a$

Now, $v^2=u^2-2ad$

Now, substituting the values,

$\Rightarrow a=\frac{u^2}{2d}=\frac{125^2}{2\times 9^2\times 60}m/s^2$

$\Rightarrow a=1.60 m/s^2$