Question

A certain oscillator has equation of motion

x¨+4x=0.
The particle is initially at the point x= 1.23 when it is projected towards the origin with a speed 1.42. What is the amplitude of these oscillations to 2 decimal places

Answer 1

in simple harmonic motion, the formula for finding amplitude is:

$a=-\omega^2x$

where, $a=$ amplitude, $\omega=$ angular frequency,$x=$ Displacement