Solution
According to given theory of question
k×velocity×massk\times velocity\times massk×velocity×mass =displacement
Putting dimension of velocity and mass
k=displacementvelocity×Massk=\frac{displacement}{velocity\times Mass}k=velocity×Massdisplacement
k=metermeter×Kgseck=\frac{meter}{\frac{meter\times Kg}{sec}}k=secmeter×Kgmeter
k=secKgk=\frac{sec}{Kg}k=Kgsec or [M−1L0T1][M^{-1}L^{0}T^{1}][M−1L0T1]
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