A baseball bat with 100. J of energy strikes a ball with a mass of 150. g. The energy transfer is only 20.0 % efficient. Calculate the initial speed of the ball.
A=Q+EkA = Q+E_kA=Q+Ek
Ek=20∗A100=20 JE_k = \frac{20*A}{100}=20\text{ J}Ek=10020∗A=20 J
Ek=mV22; V=Ek∗2m=20∗20.150=≈16.33 msE_k=\frac{mV^2}{2};\ V=\sqrt{\frac{E_k*2}{m}}=\sqrt{\frac{20*2}{0.150}}= \approx16.33\ \frac{m}{s}Ek=2mV2; V=mEk∗2=0.15020∗2=≈16.33 sm
Answer:V=≈16.33 msV= \approx16.33\ \frac{m}{s}V=≈16.33 sm
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