Answer to Question #140209 in Classical Mechanics for Tabatha Clow

Question

Vector = 6.0 m and points 30° south of east. Vector = 4.0 m and points 30° east of south. The resultant vector + is given by

Answer 1

Solution

Magnitude of vector A= 6 m

Magnitude of vector B=4 m

Angle between A and B vectors

$\theta=30^°$

So resultant vector

$R=\sqrt{A^2+B^2+2AB\cos\theta}$

$R=\sqrt{6^2+4^2+2\times6\times4\cos 30^°}\\R=9.67m$