How thick of a concrete wall is required to stop a 6lb round fired at mach six?
solution
mass of round(m)=6 lb=2.72 kg
velocity(u)=7350.26 km/h=2041.7 ms
by first equation of motion
v=u - at
v=0 m/s
u=at
and
"v^2=u^2-2as"
"s=\\frac{u^2}{2a}"
"s=\\frac{ut}{2}"
"s=1020.85t\\space m"
so thickness required is 1020.85t meter.
Comments
Leave a comment