Question

How thick of a concrete wall is required to stop a 6lb round fired at mach six?

Answer 1

solution

mass of round(m)=6 lb=2.72 kg

velocity(u)=7350.26 km/h=2041.7 ms

by first equation of motion

v=u - at

v=0 m/s

u=at

and

$v^2=u^2-2as$

$s=\frac{u^2}{2a}$

$s=\frac{ut}{2}$

$s=1020.85t\space m$

so thickness required is 1020.85t meter.