Answer to Question #137916 in Classical Mechanics for Viccy

Question #137916
A shell acquires the initial velocity v = 320 m/s, having made n = 2.0 turns inside the barrel whose length is equal to l = 2.0 m. Assuming that the shell moves inside the barrel with a uniform acceleration, find the angular velocity of its axial rotation at the moment when the shell escapes the barrel.
1
Expert's answer
2020-10-13T07:13:36-0400

Solution

In this case angular acceleration can be expressed as below

ω=2πnvl\omega=\frac{2\pi nv}{l}

Putting values

n=2

v=320m/s

l=2

ω=2×3.14×2×3202\omega=\frac{2\times 3.14\times2\times320}{2}

ω=2009.6\omega=2009.6 rad/s2rad/s^2


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