Solution
In this case angular acceleration can be expressed as below
ω=2πnvl\omega=\frac{2\pi nv}{l}ω=l2πnv
Putting values
n=2
v=320m/s
l=2
ω=2×3.14×2×3202\omega=\frac{2\times 3.14\times2\times320}{2}ω=22×3.14×2×320
ω=2009.6\omega=2009.6ω=2009.6 rad/s2rad/s^2rad/s2
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