Answer to Question #137771 in Classical Mechanics for A
A particle is moving under gravity in a medium whose resistance is mkv^4. Find the motion where v is velocity
1
2020-10-15T03:11:34-0400
ma=mg−mkv4a=dtdv=g−kv4
c1+t=4g43k41(−log(g41−k41v)+log(g41+k41v)+2tan−1(g41k41v)
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