A bus is moving with a= 5m/s2 from rest find its velocity after2sec.
solution
given data
initial velocity(u)=0 m/s
acceleration (a)=5 m/s^2
By using the first equation of motion
v=u+atv=u+atv=u+at
at t=2 sec it's velocity will be
v=0+5×2=10m/sv=0+5\times2=10 m/sv=0+5×2=10m/s
velocity after 2 second will be 10 m/s.
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