solution
given data
weight of sled (W)=150 N
slope of hill=240
so mass of sled (m)="\\frac{150}{9.8}=15.31kg"
when sled will be released then it will come down due to the force of gravity witch is parallel to the slope of hill
so
"150\\sin20=ma"
"a" =acceleration of sled when released
"a=\\frac{150\\times.40}{15.31}=3.9\\text m\/s^2"
so acceleration of sled will be 3.9m/s^2
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