Answer to Question #135177 in Classical Mechanics for Viccy

Question #135177
Two particles each of rest mass m collide head-on and stick together. Before collision, the
speed of each mass was 0.6 times the speed of light in free space. The mass of the final
entity is
1
Expert's answer
2020-09-29T09:42:23-0400


Eintial=EfinalE_intial=E_final


Finalvelocity=0Final velocity=0


MC21(0.6)2+MC21(0.6)2=MC21(0)\frac {MC^2}{\sqrt1-(0.6)^2}+\frac {MC^2}{\sqrt1-(0.6)^2}= \frac {MC^2}{\sqrt1-(0)}



2MC20.8\frac{2MC^2}{0.8}



M=5m2M=\frac{5m}{2}



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