Solution
According to given data of question intensity can be expressed as below
"I=A.\\frac{q^2 a^2 sin^2\\theta}{r^2}"
Then intensities ratio can be expressed as
"\\frac{I_2}{I_1}=\\frac{q_2^2 a_2^2 }{q_1^2 a_1^2}"
Using the all given data in question
Intensity in second case is written as
"{I_2}=I_1\\frac{4e^2 4a^2 }{e^2 a^2}"
"I_2=16I" where I1=I
Therefore intensity is 16I in second case.
Comments
Leave a comment