solution-
given data
energy of system(E)="\\frac{bS^3}{VN}"
by applying the first law of thermodynamics
"TdS=dE+pdV"
and
"dE=TdS-pdV"
at the constant volume change in internal energy with respect to entropy is known as temperature
so,
"(\\frac{\\partial E}{\\partial S})_v=T" .......eq1
by putting the value of E in equation 1
"(\\frac{\\partial\\frac{bS^3}{VN} }{\\partial S})_v=T"
and by partial derivative
temperature can be shown as below
"T=3\\frac{bS^2}{VN}"
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