Solution
Current in primary coil(Ip) =10A
Transformation ratio (K) =20
Relationship between currents and transformation ratio is given by
IpIs=K\frac{I_p}{I_s}=KIsIp=K
Therefore
Current in secondary coil
Is=IpK=1020=0.5AI_s=\frac{I_p}{K}=\frac{10}{20}=0.5AIs=KIp=2010=0.5A
So current in secondary coil is 0.5A.
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