SOLUTION
given data
force applied(F)=2N
perpendicular distance(d)=4m
torque can be given as
τ=Fdsinθ\tau=Fdsin\thetaτ=Fdsinθ
force is perpendicular to distance so angle wiil be π2rad\frac{\pi}{2}rad2πrad
τ=2×4sinπ2\tau=2\times4sin\frac{\pi}{2}τ=2×4sin2π
τ=8Nm\tau=8Nmτ=8Nm
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment