Answer to Question #133060 in Classical Mechanics for Namish Batra

Question

a train starting from a railway station and moving with uniform acceleration attains a speed of 40km/h in 10 minutes find its aaceleration

Answer 1

As per the given question,

Initial velocity of train $(u)=0$

Final speed of the train $(v)=40km/hour = \dfrac{40\times 1000m}{3600sec}=\dfrac{100 m}{9sec}$

Time $(t)=10min = 10\times 60sec = 600sec$

Let the acceleration of the train is $=a$

We know that $v=u+at$

Now, substituting the values,

$\dfrac{100m}{9sec}=0+a\times 600 sec$

$\Rightarrow a = \dfrac{100m}{9\times 600sec^2}$

$\Rightarrow a = \dfrac{1}{18}m/sec^2$

$\Rightarrow a = 0.056m/sec^2$