Answer to Question #131534 in Classical Mechanics for Rethabile

Question #131534
A child of mass m is released from rest at the top of a water slide, at height h = 850.0 cm above the bottom of the slide. Assuming that the slide is frictionless because of the water on it, the child’s speed at the bottom of the slide is…..
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Expert's answer
2020-09-02T12:14:21-0400

As per the given question,

Mass of the children=m

Height of the water slide(h)=850cm=8.5m(h)=850cm =8.5m

Let the gravitational acceleration is (g)=9.8m/sec2(g)=9.8m/sec^2

The speed of the child, at the bottom of the slide =v

Initial velocity of the child=u,

v2=u2+2ghv^2=u^2+2gh

Now, substituting the values,

v2=0+2×9.8×8.5m\Rightarrow v^2=0+2\times 9.8\times 8.5m

v=166.6m/sec\Rightarrow v=\sqrt{166.6} m/sec

v=12.90m/sec\Rightarrow v=12.90 m/sec


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