Answer to Question #128131 in Classical Mechanics for Hassam

Question #128131
A DVD is initially at rest so that the
line PQ on the disc’s surface is along
the +x-axis. The disc begins to turn
with a constant z = 5.0 rad/s2.
At t = 0.40 s, what is the angle
between the line PQ and the +x-axis?
1
Expert's answer
2020-08-02T15:17:07-0400

As per the given question,

Initial angular velocity of the disc(ω)=0rad/sec(\omega)=0 rad/sec

Angular acceleration of the disc (α)=5rad/sec2(\alpha)=5 rad/sec^2

angle between the line PQ and x axis=θ\theta

time t=0.4sec

θ=ωt+αt22\theta= \omega t+\frac{\alpha t^2}{2}

Now, substituting the values,

θ=0+5×0.422\theta = 0+\frac{5\times 0.4^2}{2}

θ=0.4radian.\Rightarrow \theta =0.4 radian.


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Comments

Hassam
03.08.20, 02:15

Thankyousomuch ☺️ the answer was correct

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