As per the given question,
Initial angular velocity of the disc(ω)=0rad/sec(\omega)=0 rad/sec(ω)=0rad/sec
Angular acceleration of the disc (α)=5rad/sec2(\alpha)=5 rad/sec^2(α)=5rad/sec2
angle between the line PQ and x axis=θ\thetaθ
time t=0.4sec
θ=ωt+αt22\theta= \omega t+\frac{\alpha t^2}{2}θ=ωt+2αt2
Now, substituting the values,
θ=0+5×0.422\theta = 0+\frac{5\times 0.4^2}{2}θ=0+25×0.42
⇒θ=0.4radian.\Rightarrow \theta =0.4 radian.⇒θ=0.4radian.
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Thankyousomuch ☺️ the answer was correct
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