As per the given question,
c=0.1μFc=0.1\mu Fc=0.1μF
L=10mh=10×10−3hL=10mh =10\times 10^{-3}hL=10mh=10×10−3h
R=200ΩR=200\OmegaR=200Ω
Z=R2+XL−XcZ=\sqrt{R^2+{X_L-X_c}}Z=R2+XL−Xc
Resonating frequency,
ω=1LC\omega=\frac{1}{\sqrt{LC}}ω=LC1
Now, substituting the values,
ω=10.1×10−6×10×10−3\omega=\frac{1}{\sqrt{0.1\times 10^{-6}\times 10\times 10^{-3}}}ω=0.1×10−6×10×10−31
⇒ω=110×10−10\Rightarrow \omega =\frac{1}{\sqrt{10\times10^{-10}}}⇒ω=10×10−101
⇒ω=10510\Rightarrow \omega=\frac{10^5}{\sqrt{10}}⇒ω=10105
⇒2πf=10510\Rightarrow 2\pi f =\frac{10^5}{\sqrt{10}}⇒2πf=10105
⇒f=1052π10sec−1\Rightarrow f=\frac{10^5}{2\pi \sqrt{10}}sec^{-1}⇒f=2π10105sec−1
⇒f=10519.87sec−1\Rightarrow f=\frac{10^5}{19.87}sec^{-1}⇒f=19.87105sec−1
⇒f=5×103sec−1\Rightarrow f=5\times 10^3 sec^{-1}⇒f=5×103sec−1
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