Question

If a simple pendulum oscillates with amplitude of 50mm and time period of 2s, then its maximum velocity is..
1 : 0.10 m/s
2 : 0.16 m/s
3 : 0.24 m/s
4 : 0.32 m/s

Answer 1

Relationship of velocity and displacement 

$v=\omega\sqrt{A^2-x^2}$

$V=A\omega=A\frac{2\pi}{T}$

$50\times10^{-3}\times\frac{2\pi}{2}$

$V=50\times10^{-3}\times3.14$

$=0.16m/s$

Therefore, option 2 : 0.16 m/s is correct