Answer to Question #127528 in Classical Mechanics for Ashley

Question

A simple harmonic oscillator has an amplitude of 3.50 cm and a maximum speed of 26.0 cm/s. What is its speed when the displacement is 1.75 cm?
1 : 12.0 cm/s
2 : 22.5 cm/s
3 : 14.2 cm/s
4 : 15.0 cm/s
5 : 17.0 cm/s

Answer 1

$X_m=3.50$

$\omega X_m=26cm/s$

$\omega=\frac{26}{3.5}=7.43$

$v=\omega \sqrt {X^2_m-X}$

$8\sqrt{0.035^2-0.017^2} =0.225$

which is $22.5cm/s$