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Question #126751
Two force vectors with |A| = 65 N and |B| = 76 N make an angle of 45° with each other. C is the sum of these two vectors. Calculate the magnitude of C
Expert's answer
The Cosine Rule says
C
=
A
2
+
B
2
−
2
A
B
cos
θ
=
6
5
2
+
7
6
2
−
2
×
65
×
76
cos
4
5
∘
=
55
N
C=\sqrt{A^2+B^2-2AB\cos \theta}=\\ \sqrt{65^2+76^2-2\times 65\times 76\cos 45^{\circ}}=55\:\rm N
C
=
A
2
+
B
2
−
2
A
B
cos
θ
=
6
5
2
+
7
6
2
−
2
×
65
×
76
cos
4
5
∘
=
55
N
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on Jan 2024
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