Answer to Question #126443 in Classical Mechanics for Rimsha Ahmed

Question #126443
Kindly, tell me how this equation will be solved for distance "d", please.

(d/2)/12 + (d/2)/15 = 3

Thank you.
1
Expert's answer
2020-07-16T10:57:49-0400

Given,

d212+d215=3\dfrac{\frac{d}{2}}{12}+\dfrac{\frac{d}{2}}{15}=3

Let, p=d2p=\frac{d}{2} ,thus new equation will be

p12+p15=3\frac{p}{12}+\frac{p}{15}=3

Now,

LCM(12,15)=60\text{LCM}(12,15)=60

Thus,

5p60+4p60=3    9p60=3\frac{5p}{60}+\frac{4p}{60}=3\\\implies \frac{9p}{60}=3

Multiply both side of the above equation by 6060 we get

9p=1809p=180

Now divide both side of the above equation by 99 ,thus p=20p=20 but p=d2p=\frac{d}{2} ,hence

d/2=20    d=40d/2=20\implies d=40


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Rimsha Ahmed
30.07.20, 15:31

I really appreciate it. Thank you for the response.

Leave a comment