Answer to Question #126105 in Classical Mechanics for Mirza Adnan Baig

Question #126105

A fermentation broth is required to be mixed turbulently using an impeller. The density & viscosity of broth is found to be 850 kg/m3 and 22 Pas. What must be the minimum diameter of the impeller to achieve Reynolds number of 5600, if impeller is required to rotate at 100 revolution per minute?

1
Expert's answer
2020-07-13T11:42:20-0400

The stirrer speed is


ω=10060=1.67 s1.\omega=\frac{100}{60}=1.67\text{ s}^{-1}.

The expression for Reynolds number:


R=ρωD2μ,R=\frac{\rho\omega D^2}{\mu},


the diameter is


D=μRρω=2256008501.67=9.3 m.D=\sqrt{\frac{\mu R}{\rho\omega}}=\sqrt{\frac{22 \cdot5600}{850\cdot1.67}}=9.3\text{ m}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment