As per the question,
mass of the trolley (m1)=3.3kg
mass connected with the trolley with the help of the string (m2)=2.2kg
chord runs through the pulley,
Let the acceleration of the trolley = a and tension in the string is T,
Now,
a)
m1g−T=m1a
⇒3.3g−T=3.3a−−−−(i)
and
T−m2g=m2a
⇒T−2.2g=2.2a−−−(ii)
from equation (i) and (ii),
⇒3.3g−2.2g=5.5a
⇒a=5.51.1gm/sec2
and
b)
T=2.2g+2.2a=2.2g+2.2×5.51.1g
⇒T=2.2g+0.44g=2.64gN
Hence , clamping force on the card=2T
=2×2.64g=5.28gN
Comments
Leave a comment