Calculate the theoretical value of final velocity applying conservation of energy principlr:
"mgh+\\frac{mv_1^2}{2}=\\frac{mv_\\text{theor}^2}{2},\\\\\n\\space\\\\\nv_\\text{theor}=\\sqrt{2gh+v_1^2}=24.8\\text{ m\/s}." Since the real final velocity was 20 m, the efficiency is
"\\eta=\\frac{v_\\text{real}}{v_\\text{theor}}100\\%=\\frac{20}{24.8}100\\%=81\\%."
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