Question #118119
A ball is tied to the end of a cable of negligible mass. The ball is spun in a circle with a radius 2.00 m making 7.00 revolutions every 10.0 seconds. What is the magnitude of the acceleration of the ball?
1 : 67.9 m/s2
2 : 38.7 m/s2
3 : 29.3 m/s2
4 : 14.8 m/s2
5 : 74.2 m/s2
1
Expert's answer
2020-05-29T10:09:03-0400

The acceleration of the ball will be


a=ω2r=(2πn)2r= =(2πNT)2r=(2π710)22=38.7 m/s2.a=\omega^2 r=(2\pi n)^2r=\\\space\\=\bigg(2\pi \frac{N}{T}\bigg)^2r=\bigg(2\pi\frac{7}{10}\bigg)^2\cdot2=38.7\text{ m/s}^2.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS