A particle of mass 3 units moves in xy plane under influence of a force field having potential V equal to 12x(3y-4x).The particle starts at time t=0 from rest and the point with position vector 10i-10j. 1.set up differential equations and conditions describing the motion 2.solve the equations in (1) 3.find the position at any time 4.Find the velocity at any time
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Expert's answer
2020-05-25T11:01:32-0400
We are given the potential of the field = 12x(3y−4x)
field = ∂x∂Vi+∂y∂Vj+∂z∂Vz =(36y−96x)i+36xj
here the field will be equal to the acceleration
as we can see that the components of the field are interdependent on each other
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