For Hooke's law "F = Ke"
⟹"\\frac Fe=K"
"\\frac{f_1}{e_1}=\\frac{f_2}{e_2}"
Let the original length=t0
therefore "e_1=(36\u2212t_0)" cm; "e_2=(46\u2212t_0)" cm
if "f_1=40N\\ \\& \\ f_2=60N"
"Then \\ \\frac{40}{\n\n36\u2212t_0}=\\frac{60}{(45\u2212t_0)}"
⟹"40(45\u2212t_0)=60(36\u2212t_0)"
therefore "1800\u221240t_0 = 2160\u221260t_0"
"60t_0\u221240t_0=2160\u22121800"
"20t_0 = 360"
"t_0 = 18cm"
Comments
Leave a comment