Balancing forces
kx=makx=makx=ma
k×0.05=50×10−3×0.8×10k\times0.05=50\times10^{-3}\times0.8\times10k×0.05=50×10−3×0.8×10
k=80k=80k=80
change in elastic potential energy = 12kx2=12×80×0.05×0.05=0.1J\frac12kx^2=\frac12\times80\times0.05\times0.05=0.1 J21kx2=21×80×0.05×0.05=0.1J
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