Answer to Question #115458 in Classical Mechanics for Lizwi

Question #115458
A box of inertia m is pulled with a constant acceleration a along a horizontal frictionless floor by a wire that makes an angle of 15° above the horizontal. If T is the tension in this wire, then what is T compared to ma? Is T=ma? Is T<ma? Is T>ma?
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Expert's answer
2020-05-13T09:56:37-0400


Let's investigate forces, acting on a box. It's a gravity force, reaction force and tension force of the rope. Writing equation of motion in horizontal projection, we have: Tcos15o=maT\cos{15^o}=m a. From this equation we obtain: T=1cos15omaT=\dfrac{1}{\cos{15^o}}ma. As cos15o<1\cos{15^o}<1, so 1cos15o>1\dfrac{1}{\cos{15^o}}>1, thus T>maT>ma


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