As per the given question,
initial speed of the skateboard"(u)=4m\/sec"
final speed of the Dan "(v)=8.0 m\/sec"
Dan's mass (M)=50kg
skateboards mass (m) = 5.0kg
Let the final speed of the skateboards =V
Applying the conservation of momentum,
"\\Rightarrow (m+M)u=-M\\times 8+m\\times V"
"\\Rightarrow V=\\dfrac{(m+M)u}{m}+\\dfrac{M\\times 8}{m}"
"\\Rightarrow V=\\dfrac{55\\times 4+8\\times 5}{5}=52 m\/sec"
Comments
Leave a comment