As per the given question,
initial speed of the skateboard(u)=4m/sec
final speed of the Dan (v)=8.0m/sec
Dan's mass (M)=50kg
skateboards mass (m) = 5.0kg
Let the final speed of the skateboards =V
Applying the conservation of momentum,
⇒(m+M)u=−M×8+m×V
⇒V=m(m+M)u+mM×8
⇒V=555×4+8×5=52m/sec
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