As per the question,
Distance travel by the truck ="10^9 m"
Average speed (v)"=80 km\/hr=80\\times \\dfrac{1000}{3600}=\\dfrac{200}{9}m \/sec"
turn rate "=2000 revolution\/ min=\\dfrac{2000}{60} revolution\/sec"
time "t=\\dfrac{10^9\\times 9}{200} sec"
Hence total number of revolution =time taken in one revolution x total time
"=\\dfrac{2000}{60}\\times \\dfrac{10^9\\times 9}{200}"
"=15\\times 10^8"
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