Answer to Question #108118 in Classical Mechanics for VIVEK SINGH

Question #108118
(a) What is the approximate force of gravity on a 70-kg person due to the Andromeda galaxy, assuming its total mass is 1013 that of our Sun and acts like a single mass 2 Mly away?
1
Expert's answer
2020-04-06T09:20:23-0400

1 Mly =9.45×1021m9.45\times10^{21}m

2 Mly =18.9×1021m18.9\times10^{21}m

mass of sun =1.989×1030kg1.989 × 10^{30} kg

mass of  Andromeda=1013×1.989×1030=2×1031kg1013\times1.989\times10^{30}=2\times10^{31}kg

Force of gravity is given by GMmr2G\frac{Mm}{r^2}

Force = 6.67259×1011×2×1031×70(1.89×1030)2=2.61×1040N6.67259 \times 10^{-11}\times\frac{2\times10^{31}\times70}{(1.89\times10^{30})^2}=2.61\times10^{-40}N


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