Question #107738
a 15.0kg object experiences a 20 N force pulling at 30.0 degrees south of west, a force of 30 N pulling from the west, and a 45 N force pulling from the north. What is the acceleration experienced by the object?
1
Expert's answer
2020-04-05T14:42:40-0400

I have pasted a picture of the question which will show the actual direction of forces



Let's resolve the force  20 N at 30.0 degrees south of west

20N sin30o will act in the south direction =10 N in the south

20 N cos300 will sct in the west direction =103\sqrt3 N in the West

Lets find the resultant of all the forces

We get 30 N acts in the North direction and 30+103\sqrt3 N in the West direction

converting this into vector form

F=(30+103)i+30jF=-(30+10\sqrt3)i+30j

Force =ma

a=(2+233)i+2ja=-(2+\frac{2\sqrt3}{3})i+2j


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS