The Coriolis force will be
"F_c=2m\\Omega v\\text{ sin}\\lambda=\\\\\n\\space\\\\\n=2\\cdot6\\cdot(7.3\\cdot10^{-5})\\cdot\\bigg(50\\cdot\\frac{1000}{3600}\\bigg)\\cdot\\text{sin}30^\\circ=\\\\\n\\space\\\\\n=6.08\\cdot10^{-3}\\text{ N}."Notice that in the equation above Ω is the earth's angular velocity:
"\\Omega=\\frac{\\Delta\\phi}{\\Delta t}=\\frac{2\\pi}{24\\cdot3600}=7.27\\cdot10^{-5}\\text{ s}^{-1}."
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