Question #105238
A cable car of mass 1200 kg moves 2km up a slope inclined at 30 degrees to the horizontal at a constant speed. If the resistance to motion is 400N find the work done by the tension in the cable.
1
Expert's answer
2020-03-13T10:47:13-0400


First, find the tension:


Ox:TRmg sin30=0,T=R+mg sin30.WT=Td=d(R+mg sin30)==2000(400+12009.8 sin30)=12.56106 J.Ox: T-R-mg\text{ sin}30^\circ=0,\\ T=R+mg\text{ sin}30^\circ.\\ W_T=Td=d(R+mg\text{ sin}30^\circ)=\\=2000(400+1200\cdot9.8\text{ sin}30^\circ)=12.56\cdot10^6\text{ J}.



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