Let the initial angular speed"(\\omega_o)" =0
Final angular speed"(\\omega)" = 2 rev/sec
time (t) =8sec
let the angular acceleration be "\\alpha" and
Now, we know that,
"\\Rightarrow \\omega=\\omega_o+\\alpha t"
"\\Rightarrow \\omega=0+\\alpha t"
"\\alpha=\\dfrac{\\omega}{t}=\\dfrac{2}{8}=0.25 rev\/sec^2"
As per the second condition, after switched off,
After switching off, it is getting stopped in 12 sec,
"\\theta=\\omega t-\\dfrac{\\alpha t^2}{2}"
"\\theta= 2\\times 12-\\dfrac{0.25\\times 144}{2}=24-18=6"
"\\theta= 2\\pi n =6"
so "n=\\dfrac{6}{2\\pi}=\\dfrac{3}{\\pi}"
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