As per the given question,
Drag coefficient "C_d=0.3"
Frontal area "= 1.9m^2"
Mass =1.2 tonnes
Coefficient of rolling resistance Cr=0.012
Rolling resistance "F_r\u200b = C_rN"
Where N = Normal reaction.
i) Speed "= 110 Kph=\\dfrac{110\\times 1000}{3600}=30.56m \/sec"
Friction force does not depend on the velocity,
So "F_r= C_rN=C_r mg=0.012\\times1200\\times9.8 =141.12 N"
ii) Power P="F_r v=141.12\\times30.56=4312.67J\/sec \\simeq 4.31 Kwatt"
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