Question #104304

1. Jim's mass is m = 62 kg. He is standing in a lift, with no motion relative to the lift.


a) The lift accelerates upwards at 2.0 m.s^-2. What is the magnitude of the force the floor of the lift exerts on Jim?

b) Later, the lift accelerates downwards at 2.0 m.s^-2. What is the magnitude of the force the floor of the lift exerts on Jim?

c) Just suppose that the lift were to accelerate downwards at 10.0 m.s^-2. What force would the floor of the lift exert on Jim?

Expert's answer

a)


N1=m(a+g)=62(2+9.8)=730 NN_1=m(a+g)=62(2+9.8)=730\ N

b)


N2=m(ga)=62(9.82)=480 NN_2=m(g-a)=62(9.8-2)=480\ N

c)


N3=0 NN_3=0\ N

For gag\leq a there is no force between floor and Jim. He would accelerate upwards relative lift.


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