1. Jim's mass is m = 62 kg. He is standing in a lift, with no motion relative to the lift.
a) The lift accelerates upwards at 2.0 m.s^-2. What is the magnitude of the force the floor of the lift exerts on Jim?
b) Later, the lift accelerates downwards at 2.0 m.s^-2. What is the magnitude of the force the floor of the lift exerts on Jim?
c) Just suppose that the lift were to accelerate downwards at 10.0 m.s^-2. What force would the floor of the lift exert on Jim?
1
Expert's answer
2020-03-05T09:37:38-0500
a)
"N_1=m(a+g)=62(2+9.8)=730\\ N"
b)
"N_2=m(g-a)=62(9.8-2)=480\\ N"
c)
"N_3=0\\ N"
For "g\\leq a" there is no force between floor and Jim. He would accelerate upwards relative lift.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment