Question #104291

Week 4


1. This artist's conception imagines a 'wheel-shaped' space station. The idea is that the 'wheel' would turn on its axis at a rate such that the acceleration in the rim of the wheel would be 9.8 m/s^2. (This would make inhabitants feel as though they had their normal weight.) Suppose that the radius of the wheel is 1.0 x 10^2 m. What is the required period of rotation of the space station about its axis? (Follow the significant number for the final answer).

Expert's answer

As per the question,

Acceleration in the rim of the wheel is (a)=9.8m/sec2(a)=9.8 m/sec^2

Radius of the wheel (R)=1.0×102m1.0 \times 10^2 m

We know that a=Rω2a=R\omega^2

ω=\omega= angular velocity of the wheel

We know that angular velocity (ω)=2πT(\omega)=\dfrac{2\pi}{T}

where T is the time period.

So,

9.8m/sec2=1.0×2πT9.8 m/sec^2=1.0\times \dfrac{2\pi}{T}

T=2π9.8=0.64sec\Rightarrow T=\dfrac{2\pi}{9.8}=0.64 sec

or 0.6 sec


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