As per the question,
Acceleration in the rim of the wheel is (a)=9.8m/sec2
Radius of the wheel (R)=1.0×102m
We know that a=Rω2
ω= angular velocity of the wheel
We know that angular velocity (ω)=T2π
where T is the time period.
So,
9.8m/sec2=1.0×T2π
⇒T=9.82π=0.64sec
or 0.6 sec
Comments
The answer is wrong as the author forgot to perform the square root. the correct answer will be 20 s.
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