Answer to Question #103635 in Classical Mechanics for Abdulkadir

Question

Q1.Find the direction and magnitude of an electric field that exerts a 4.8×10*17N westward force on an electron
b. What magnitude and direction force does this field exert on a proton

Answer 1

1)

Force = charge * Electric field

electric field = Force/charge = $4.8*10^{17}/1.6*10^{-19}=3*10^{36}N/C$

the direction of the electric filed will be opposite to that of direction of Force as electric carries negative charge , Hence the direction of electric field will be in eastward direction

b) the magnitude of force acting on proton will be same as electron just the direction will be opposite as proton carries positive charge hence

force= $4.8*10^{17}N$ in the eastward direction