As per the question,
the mass of the obje ct =56kg
initial velocity of the object = 8m/sec
let before the explosion, object was moving in the x axis.
After the explodes,
mass of A=20kg
velocity of the piece A=20m/sec along the x axis
mass of the piece B=16kg
velocity of the piece B=15m/sec
B is moving at 45 with x axis.
Mass of the object c=56-20-16=20 kg
let the velocity of the c = "v"
let C is moving at an angle "\\theta" with the horizontal.
Now applying the conservation of linear momentum
"56\\times 8=20\\times20+16\\times 15 \\cos 45+20\\times v\\cos\\theta"
"488=400+120\\sqrt{2}+20v\\cos\\theta"
"v\\cos\\theta=88-120\\sqrt{2}--------(i)"
Similarly,
"20v\\sin \\theta=16\\times\\sin 45------------(ii)"
equation (ii) is dividing by equation (i)
"\\tan\\theta=\\dfrac{4\\sin 45}{5(88-120\\sqrt{2})}"
"\\tan\\theta=-0.007"
"\\theta=0.4^\\circ"
"v\\cos\\theta=88-120\\sqrt{2}"
"v\\cos\\theta=\\dfrac{88-120\\sqrt{2}}{\\cos (0.4)}=-81.70 m\/sec"
So, piece C will move along the negative x axis with the velocity -81.7 m/sec
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