Answer to Question #102921 in Classical Mechanics for Patrick Kariuki

Question #102921
A 210 kg mass initially at rest on a smooth horizontal plane is acted upon by a force F parallel with the plane. If F is 1.4 tN where t is time in seconds, find for an interval of 30 seconds from rest: (a) the impulse (b) the velocity (c) the average force producing the same impulse.
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Expert's answer
2020-02-13T09:04:05-0500

Impulse is given by Fdt\intop Fdt

(a) Impulse= 030\intop_0^{30} 1.4tdt1.4tdt =1.4×450=630Ns=1.4\times450=630Ns


(b) Impulse= change in momentum =Δp=m(vfvi)=\Delta p=m(v_f-v_i)

630=210(v0)v=3m/sec630=210(v-0) \newline v=3m/sec


(c) Impulse=avg.force×timeImpulse = avg. force \times time

630=Favg×30Favg=21N630=F_{avg}\times30 \newline F_{avg}=21 N


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