Question #102738
A 40 tonnes rail car travels at 4km/h collides with a 100 tonnes wagon moving on the same track in the opposite direction at 1.2 km/h. Find their velocities immediately after impact assuming no loss of energy.
1
Expert's answer
2020-02-11T10:09:43-0500

Weight of the rail car (m1)(m_1) =40tons

Velocity (u1)(u_1) =4Km/hour

Mass of the wagon(m2)(m_2) =100 tons

Velocity of wagon(u2)(u_2) =1.2k/hour

Let the final velocity of the rail wagon(v1v_1) and the final velocity of wagon (v2v_2 )

Now, applying the conservation of the linear momentum.

m1u1+m2u2=m1v1+m2v2m_1u_1+m_2u_2=m_1v_1+m_2v_2

40v1+100v2=40×4100×1.240v_1+100v_2=40 \times4-100\times1.2

40v1+100v2=160120=40\Rightarrow 40v_1+100v_2=160-120=40

2v1+5v2=2(i)\Rightarrow 2v_1+5v_2=2--------(i)

The collision is elastic,

So, e=1

e=v2v1u1u2e=\dfrac{v_2-v_1}{u_1-u_2}

1=v2v141.2\Rightarrow 1=\dfrac{v_2-v_1}{4-1.2}

v2v1=2.8(ii)v_2-v_1=2.8----(ii)

From equation (i) and (ii)


v1=127km/hourv_1=\dfrac{-12}{7} km/hour


v2=7.67km/hourv_2=\dfrac{7.6}{7}km/hour



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Comments

Assignment Expert
12.02.20, 17:02

Yes, since the collision is elastic, the car and wagon will not merge after impact.

No-am
11.02.20, 19:30

So it would be wrong to assume that the car and the wagon merge after impact?

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