Answer to Question #102048 in Classical Mechanics for Sky Seo

Question #102048
An object is moving along the plain surface by the force F = (5x)i - (3y)j.
a) How much work was done if the particle moved from (0,0) to (-6,8)?
b) What is the change in kinetic energy?
c) If the change in location occurred in 0.2 seconds, what is the average power?
1
Expert's answer
2020-01-31T10:36:50-0500

a)


W=F(r2r1)W=\bold{F(r_2-r_1)}

W=5(x22)063(y22)08W=5\left(\frac{x^2}{2}\right)^{-6}_0-3\left(\frac{y^2}{2}\right)^{8}_0

W=5(622)3(822)=6 JW=5\left(\frac{6^2}{2}\right)-3\left(\frac{8^2}{2}\right)=-6\ J

b)


ΔK=W=6 J\Delta K=W=-6\ J

c)


P=ΔKΔt=60.2=30 WP=\frac{\Delta K}{\Delta t}=\frac{-6}{0.2}=-30\ W


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