Answer to Question #101368 in Classical Mechanics for Victoria Winters

Question

A horizontal 781 N merry-go-round of radius 1.75 m is started from rest by a constant
horizontal force of 75 N applied tangentially to the merry-go-round.
Find the kinetic energy of the merry-goround after 3.97 s. The acceleration of gravity
is 9.8 m/s2
Assume the merry-go-round is a solid cylinder.
Answer in units of J.

Answer 1

$I=0.5mr^2=0.5\frac{W}{g}r^2=0.5\frac{781}{9.8}(1.75)^2=122\ kg\cdot m^2$

$I\alpha=Fr\to 122\alpha=(75)(1.75)$

Angular acceleration:

$\alpha=1.08\frac{rad}{s^2}$

Angular velocity:

$\omega=\alpha t=1.08(3.97)=4.29\frac{rad}{s}$

$K=0.5I\omega^2=0.5(122)(4.29)^2=1120\ J$