Answer to Question #99723 in Atomic and Nuclear Physics for Xander

Question

Write 5 fission reaction

Answer 1

$${^{235}_{92}U}+{^{1}_{0}n}\to{^{141}_{56}Ba}+{^{92}_{36}Kr}+3{^{1}_{0}n}$$

$${^{235}_{92}U}+{^{1}_{0}n}\to{^{96}_{37}Rb}+{^{137}_{55}Cs}+3{^{1}_{0}n}$$

$${^{235}_{92}U}+{^{1}_{0}n}\to{^{87}_{35}Br}+{^{146}_{57}La}+3{^{1}_{0}n}$$

$${^{235}_{92}U}+{^{1}_{0}n}\to{^{90}_{38}Sr}+{^{144}_{54}Xe}+2{^{1}_{0}n}$$

$${^{235}_{92}U}+{^{1}_{0}n}\to{^{137}_{52}Te}+{^{97}_{40}Zr}+2{^{1}_{0}n}$$